1) 55 Solution: Short Encoding of Words (ver. 2) 50 Solution: Missing Number 51 Solution: Intersection of Two Linked Lists 52 Solution: Average of Levels in Binary Tree 53 Solution: Short Encoding of Words (ver. 2) 46 Solution: Maximum Frequency Stack 47 Solution: Distribute Candies 48 Solution: Set Mismatch (ver. 1) 45 Solution: Divide Two Integers (ver. 2) 32 Solution: Letter Case Permutation 33 Solution: Container With Most Water 34 Solution: Arithmetic Slices 35 Solution: Minimum Remove to Make Valid Parentheses 36 Solution: Roman to Integer 37 Solution: Broken Calculator 38 Solution: Find the Most Competitive Subsequence 39 Solution: Longest Word in Dictionary through Deleting 40 Solution: Search a 2D Matrix II 41 Solution: Score of Parentheses 42 Solution: Shortest Unsorted Continuous Subarray 43 Solution: Validate Stack Sequences 44 Solution: Divide Two Integers (ver. 1) 31 Solution: The K Weakest Rows in a Matrix (ver. 2) 29 Solution: Sort the Matrix Diagonally 30 Solution: The K Weakest Rows in a Matrix (ver. 1) 28 Solution: Maximum Score From Removing Substrings (ver. 3 Leetcode Solutions Index 4 Solution: Minimize Deviation in Array 5 Solution: Vertical Order Traversal of a Binary Tree 6 Solution: Count Ways to Make Array With Product 7 Solution: Smallest String With A Given Numeric Value 8 Solution: Linked List Cycle 9 Solution: Path With Minimum Effort 10 Solution: Concatenation of Consecutive Binary Numbers 11 Solution: Minimum Operations to Make a Subsequence 12 Solution: Longest Harmonious Subsequence 13 Solution: Simplify Path 14 Solution: Building Boxes 15 Solution: Decode XORed Permutation 16 Solution: Binary Tree Right Side View 17 Solution: Find Kth Largest XOR Coordinate Value 18 Solution: Change Minimum Characters to Satisfy One of Three Conditions 19 Solution: Shortest Distance to a Character 20 Solution: Peeking Iterator 21 Solution: Convert BST to Greater Tree 22 Solution: Copy List with Random Pointer 23 Solution: Valid Anagram 24 Solution: Number of Steps to Reduce a Number to Zero 25 Solution: Shortest Path in Binary Matrix 26 Solution: Is Graph Bipartite? 27 Solution: Maximum Score From Removing Substrings (ver. If you like what you learn, feel free to fork □ and star ⭐ it.1 Solution: Next Permutation 2 Solution: Trim a Binary Search Tree. You can find the complete source code on my GitHub repository. Feel free to share your thoughts on this. Public class LetterCombinationsOfAPhoneNumber Complete CodeĬongratulations □! We have solved one more problem from LeetCode. The recursive call will use the stack memory equal to O(3 m × 4 n) and this will be the space complexity. Thus, the overall time complexity will be O(3 m × 4 n). Let m be the number of digits that map to 3 letters and n be the number of digits that map to 4 letters. The numbers in input string can represent strings of length of 3 or 4. We will then loop for all the characters in the string obtained in the previous step and call make recursive calls with the strings after appending the current character and the string in the previous step.If the terminating condition is not met then we will first find the letters corresponding to the current characters in the given string by referring to our mappings array.In our case, think when our recursion will stop □? It will stop when we have scanned all the characters in the given string. In the recursive function, we should have a terminating condition.This function will be called recursively. Write a helper function which will contain the crux of our logic.
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